Optimal. Leaf size=194 \[ \frac{a \left (a^2+9 b^2\right ) \tan ^7(c+d x)}{7 d}+\frac{3 a \left (a^2+3 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{a \left (a^2+b^2\right ) \tan ^3(c+d x)}{d}+\frac{3 a^2 b \sec ^8(c+d x)}{8 d}+\frac{a^3 \tan (c+d x)}{d}+\frac{a b^2 \tan ^9(c+d x)}{3 d}+\frac{b^3 \tan ^{10}(c+d x)}{10 d}+\frac{3 b^3 \tan ^8(c+d x)}{8 d}+\frac{b^3 \tan ^6(c+d x)}{2 d}+\frac{b^3 \tan ^4(c+d x)}{4 d} \]
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Rubi [A] time = 0.147028, antiderivative size = 194, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3506, 696, 1810} \[ \frac{a \left (a^2+9 b^2\right ) \tan ^7(c+d x)}{7 d}+\frac{3 a \left (a^2+3 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{a \left (a^2+b^2\right ) \tan ^3(c+d x)}{d}+\frac{3 a^2 b \sec ^8(c+d x)}{8 d}+\frac{a^3 \tan (c+d x)}{d}+\frac{a b^2 \tan ^9(c+d x)}{3 d}+\frac{b^3 \tan ^{10}(c+d x)}{10 d}+\frac{3 b^3 \tan ^8(c+d x)}{8 d}+\frac{b^3 \tan ^6(c+d x)}{2 d}+\frac{b^3 \tan ^4(c+d x)}{4 d} \]
Antiderivative was successfully verified.
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Rule 3506
Rule 696
Rule 1810
Rubi steps
\begin{align*} \int \sec ^8(c+d x) (a+b \tan (c+d x))^3 \, dx &=\frac{\operatorname{Subst}\left (\int (a+x)^3 \left (1+\frac{x^2}{b^2}\right )^3 \, dx,x,b \tan (c+d x)\right )}{b d}\\ &=\frac{3 a^2 b \sec ^8(c+d x)}{8 d}+\frac{\operatorname{Subst}\left (\int \left (1+\frac{x^2}{b^2}\right )^3 \left (-3 a^2 x+(a+x)^3\right ) \, dx,x,b \tan (c+d x)\right )}{b d}\\ &=\frac{3 a^2 b \sec ^8(c+d x)}{8 d}+\frac{\operatorname{Subst}\left (\int \left (a^3+\frac{3 a \left (a^2+b^2\right ) x^2}{b^2}+x^3+\frac{3 a \left (a^2+3 b^2\right ) x^4}{b^4}+\frac{3 x^5}{b^2}+\frac{a \left (a^2+9 b^2\right ) x^6}{b^6}+\frac{3 x^7}{b^4}+\frac{3 a x^8}{b^6}+\frac{x^9}{b^6}\right ) \, dx,x,b \tan (c+d x)\right )}{b d}\\ &=\frac{3 a^2 b \sec ^8(c+d x)}{8 d}+\frac{a^3 \tan (c+d x)}{d}+\frac{a \left (a^2+b^2\right ) \tan ^3(c+d x)}{d}+\frac{b^3 \tan ^4(c+d x)}{4 d}+\frac{3 a \left (a^2+3 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{b^3 \tan ^6(c+d x)}{2 d}+\frac{a \left (a^2+9 b^2\right ) \tan ^7(c+d x)}{7 d}+\frac{3 b^3 \tan ^8(c+d x)}{8 d}+\frac{a b^2 \tan ^9(c+d x)}{3 d}+\frac{b^3 \tan ^{10}(c+d x)}{10 d}\\ \end{align*}
Mathematica [A] time = 1.95957, size = 177, normalized size = 0.91 \[ \frac{\frac{3}{8} \left (5 a^2+b^2\right ) (a+b \tan (c+d x))^8-\frac{4}{7} a \left (5 a^2+3 b^2\right ) (a+b \tan (c+d x))^7+\frac{1}{2} \left (a^2+b^2\right ) \left (5 a^2+b^2\right ) (a+b \tan (c+d x))^6-\frac{6}{5} a \left (a^2+b^2\right )^2 (a+b \tan (c+d x))^5+\frac{1}{4} \left (a^2+b^2\right )^3 (a+b \tan (c+d x))^4+\frac{1}{10} (a+b \tan (c+d x))^{10}-\frac{2}{3} a (a+b \tan (c+d x))^9}{b^7 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 219, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ({b}^{3} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{10\, \left ( \cos \left ( dx+c \right ) \right ) ^{10}}}+{\frac{3\, \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{40\, \left ( \cos \left ( dx+c \right ) \right ) ^{8}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{20\, \left ( \cos \left ( dx+c \right ) \right ) ^{6}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{40\, \left ( \cos \left ( dx+c \right ) \right ) ^{4}}} \right ) +3\,a{b}^{2} \left ( 1/9\,{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{ \left ( \cos \left ( dx+c \right ) \right ) ^{9}}}+2/21\,{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{ \left ( \cos \left ( dx+c \right ) \right ) ^{7}}}+{\frac{8\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{105\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}}+{\frac{16\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{315\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}} \right ) +{\frac{3\,b{a}^{2}}{8\, \left ( \cos \left ( dx+c \right ) \right ) ^{8}}}-{a}^{3} \left ( -{\frac{16}{35}}-{\frac{ \left ( \sec \left ( dx+c \right ) \right ) ^{6}}{7}}-{\frac{6\, \left ( \sec \left ( dx+c \right ) \right ) ^{4}}{35}}-{\frac{8\, \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{35}} \right ) \tan \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.18849, size = 238, normalized size = 1.23 \begin{align*} \frac{84 \, b^{3} \tan \left (d x + c\right )^{10} + 280 \, a b^{2} \tan \left (d x + c\right )^{9} + 315 \,{\left (a^{2} b + b^{3}\right )} \tan \left (d x + c\right )^{8} + 120 \,{\left (a^{3} + 9 \, a b^{2}\right )} \tan \left (d x + c\right )^{7} + 420 \,{\left (3 \, a^{2} b + b^{3}\right )} \tan \left (d x + c\right )^{6} + 504 \,{\left (a^{3} + 3 \, a b^{2}\right )} \tan \left (d x + c\right )^{5} + 1260 \, a^{2} b \tan \left (d x + c\right )^{2} + 210 \,{\left (9 \, a^{2} b + b^{3}\right )} \tan \left (d x + c\right )^{4} + 840 \, a^{3} \tan \left (d x + c\right ) + 840 \,{\left (a^{3} + a b^{2}\right )} \tan \left (d x + c\right )^{3}}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.06488, size = 344, normalized size = 1.77 \begin{align*} \frac{84 \, b^{3} + 105 \,{\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2} + 8 \,{\left (16 \,{\left (3 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{9} + 8 \,{\left (3 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{7} + 6 \,{\left (3 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{5} + 35 \, a b^{2} \cos \left (d x + c\right ) + 5 \,{\left (3 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{840 \, d \cos \left (d x + c\right )^{10}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \tan{\left (c + d x \right )}\right )^{3} \sec ^{8}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.8627, size = 297, normalized size = 1.53 \begin{align*} \frac{84 \, b^{3} \tan \left (d x + c\right )^{10} + 280 \, a b^{2} \tan \left (d x + c\right )^{9} + 315 \, a^{2} b \tan \left (d x + c\right )^{8} + 315 \, b^{3} \tan \left (d x + c\right )^{8} + 120 \, a^{3} \tan \left (d x + c\right )^{7} + 1080 \, a b^{2} \tan \left (d x + c\right )^{7} + 1260 \, a^{2} b \tan \left (d x + c\right )^{6} + 420 \, b^{3} \tan \left (d x + c\right )^{6} + 504 \, a^{3} \tan \left (d x + c\right )^{5} + 1512 \, a b^{2} \tan \left (d x + c\right )^{5} + 1890 \, a^{2} b \tan \left (d x + c\right )^{4} + 210 \, b^{3} \tan \left (d x + c\right )^{4} + 840 \, a^{3} \tan \left (d x + c\right )^{3} + 840 \, a b^{2} \tan \left (d x + c\right )^{3} + 1260 \, a^{2} b \tan \left (d x + c\right )^{2} + 840 \, a^{3} \tan \left (d x + c\right )}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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